Adrian12313
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What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y – 4 = –(x – 6) and passes through the point (−2, −2)?

Respuesta :

y – 4 = –(x – 6)
y = -x + 10 

so slope = -1
perpendicular to the line  then slope = 1

passes through the point (−2, −2) then
y = mx + b
-2 = 1(-2) + b
-2 = - 2 + b 
-2 + 2 = b
  0=b 

equation:

y = x

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