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A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the
amount of energy released by the reaction.
A)
1.41 x 10-20
B)
1.57 x 10-37
C)
4.24 x 10-12
D)
5.24 x 10-46)

Respuesta :

zubyrhassan

Answer:

C) 4.24 x [tex]10^{-12}[/tex]

Explanation:

E = Δm[tex]c^{2}[/tex]

Δm = 0.0284 x 1.66 x [tex]10^{-27}[/tex] kg = 4.714x[tex]10^{-29}[/tex]kg

putting value in above equation

E = 4.714x[tex]10^{-29}[/tex]kg x (3x[tex]10^{8}[/tex][tex])^{2}[/tex] = 4.24 x [tex]10^{-12}[/tex]

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