Answer:
Three consecutive even integers would be N, N%2B2, and N%2B4.
Find three consecutive even integers such that
"6 times the sum of the first and the third""6%28N%2B%28N%2B4%29%29=6%282N%2B4%29=12N%2B24
"is" translates to "="
"8 less than 14 times the second":14%2A%28N%2B2%29-8=14N%2B28-8=14N%2B20
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12N%2B24=14N%2B20
Solve for N.
Then find N%2B2 and N%2B4.
Step-by-step explanation:
