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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 89 mph slower than the other. If the two keys are 4844 miles apart after 4 hours. What is the rate of each jet?

Respuesta :

jcherry99

Answer:

Faster jet = 650

Slower jet = 650 - 89 = 561

Step-by-step explanation:

Given

total distance apart = 4844

t = 4 hours

r1 = r

r2 = r - 89

Equations

d = r * t

r*t + (r - 89)*t = 4844

Solution

r*4 + (r - 89)*4 = 4844

4r + 4r - 356 = 4844                 Combine the left

8r - 356 = 4844                        Add 356 to both sides

8r = 4844 + 356

8r = 5200                                 Divide both sides by 8

r = 5200/8

r = 650

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