please answer this question

Answer:
[tex]f(x) = \frac{4}{ - x - 2} = = > {f}^{ - 1} (x) = \frac{2x + 4}{ - x} [/tex]
_o_o_
[tex]f(x) = - 4x + 1 = = > {f}^{ - 1} (x) = - \frac{x}{4} + \frac{1}{4} [/tex]
_o_o_
[tex]f(x) = \frac{1}{x} - 2 = = > {f}^{ - 1} (x) = \frac{1}{x + 2} [/tex]
_o_o_
[tex]f(x) = 4x = = > {f}^{ - 1} (x) = \frac{x}{4} [/tex]
I hope I helped you^_^