Answer:
x=(3/5) + (3√6)i/10, and x =(3/5) - (3√6)i/10
Step-by-step explanation:
Use the quadratic formula for ax² +bx +c=0
x= [-b±√(b²-4ac)]/2a
For, -10x² +12x -9 = 0
x= [-12 ±√(12²-4(-10)(-9)] /2(-10)
x= [-12 ±√(144-360)] /-20
x= [-12 ±√(144-360)] /-20
x= (-12 ±i√216) /-20
x= (-12 ±i6√6) /-20
so one solution will be
x= (-12 +i6√6) /-20
= (3/5) - (3√6)i/10
the second solution will be
x= (-12 - i6√6) /-20
= (3/5) + (3√6)i/10
