Respuesta :
The kinematic relations we can find the results for the different short questions are:
6. Range is R = 141.4 m
7. Range is R = 251.2 m
8. a) Time t = 4.42 s b) Range x = 55.25 m
9. a) Initial speed es v₀ = 16.16 m / s b) range is x = 11.55 m
10. Range R = 6 1.9 m
Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.
6. They ask the range of the home run.
Indicates initial velocity of 40.0 m / s and departure angle 30º
R =[tex]\frac{v_o^2 sin 2 \theta }{g}[/tex]
R = [tex]\frac{40.0^2 sin\ 2 \ 30 }{9.8 }[/tex]
R = 141.4 m
7) Ask where the golf ball arrives to the ground.
They indicate the initial velocity of 40.0 m / s and the angle of 50º
R = [tex]\frac{50.0^2 sin\ 2 \ 50 }{9.8}[/tex]
R = 251.2 m
8) They indicate the initial velocity of 25.0 m / s and an angle of 60.0º
a) Time in the air.
When the ball reaches the ground its height is zero.
y = [tex]v_{oy}[/tex] t - ½ g t²
0 = ([tex]v_{oy}[/tex] - ½ g t) t
the solution is
t=0 exit point
t = [tex]\frac{2 v_{oy}}{ g}[/tex]
vertical speed is
[tex]v_{oy}[/tex] = v₀ sin 60
Let's substitute
t = [tex]\frac{2 \ 36 \ sin 60}{9.8}[/tex]
t = 4.42 s
b) How far does the ball go
x = v₀ₓ t
x = v₀ cos 60 t
x = 25 4.42 cos 60
x = 55.25 m
9) They indicate the height of the window y = 10.0 m and the launch angle is 60º
a) What is the initial speed of the throw
As it barely reaches the window, its vertical speed is zero
[tex]v_y^2 = v_{oy}^2 - 2 g y \\0 = v_{o}^2 sin ^2 \theta - 2 g y\\ \\v_o^2 = \frac{2gy}{sin^2 \theta }[/tex]
v₀² = [tex]\frac{2 \ 9.8 \ 10.0}{9.8}[/tex]
v₀ = [tex]\sqrt{261.33}[/tex]
v₀ = 16.16 m / s
b) What is the horizontal distance
Let's find the time until we reach the window
[tex]v_y = v_{oy} - gt\\0 = v_{oy} - gt[/tex]
t = [tex]\frac{v_o sin \theta}{g}[/tex]
t = [tex]\frac{16.16 sin 60}{9.8}[/tex]
t = 1.43 s
The horizontal distance is
x = v₀ₓ t
x = 1(6.16 cos 60) 1.43
10) The range of the balloons
[tex]R = \frac{v_o^2 sin 2 \theta }{g}\\R = \frac{25.0^2 sin \ 2 \ 38 }{9.8}[/tex]
R = 6 1.9 m
In conclusion using the kinematics relations we can find the results for the different short questions are:
6. Range is R = 141.4 m
7. Range is R = 251.2 m
8. a) Time t = 4.42 s b) Range x = 55.25 m
9. a) Initial speed es v₀ = 16.16 m / s b) range is x = 11.55 m
10. Range R = 6 1.9 m
Learn more here: brainly.com/question/10903823
