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block b has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. block a has mass 3.50 kg and sits at rest on top of block b. the coefficient of static friction between the two blocks is 0.400. a horizontal force p⃗ is then applied to block a.

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jeffreypelumi

Answer:13.88

Explanation:block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5 = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88

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