Answer:
[tex]let \: the \: number \: be \: x \\ \frac{20 + x}{3} = 3x \\ \frac{3(20 + x)}{3} = (3x)3 \\ 20 + x = 9x \\ 20 = 9x - x \\ 20 = 8x \\ \frac{20}{8} = \frac{8x}{8} \\ x = 2.5[/tex]
Step-by-step explanation:
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