Answer: Choice C
Work Shown:
[tex]\frac{12^{10}}{12}\\\\\\\frac{12^{10}}{12^1}\\\\\\12^{10-1}\\\\\\12^{9}\\\\\\\frac{1}{12^{-9}}\\\\\\\left(\frac{1}{12}\right)^{-9}\\\\\\[/tex]
In the third step, I used the rule that [tex]\frac{a^b}{a^c} = a^{b-c}[/tex]. You subtract the exponents when dividing exponents of the same base.
After that, I used the rule [tex]a^{-b} = \frac{1}{a^b}[/tex] which is the same as saying [tex]a^{b} = \frac{1}{a^{-b}}[/tex] to end up with choice C as the answer.
