Answer: 16x\sqrt{2x}
Step-by-step explanation:
WELL HELLO BUDDY!
it is nice to see you again.
please,
whip out a piece of paper because we are going to be doing some QUICK MAFFS.
draw 512.
ok now draw two sticks coming out of 512
512
/ \
2 256
now lets keep going, do you see what im doing? i just divided 512 by 2
ok now lets go
512
/ \
2 256
/ \
16 16
im just looking for numbers that can DIVIDE 256 WITH NO DECIMALS!
ok so i keep going right? lets go.
the attached picture is the full diagram. scroll down to look at the picture.
WHAT I WANT YOU TO DO IS CIRCLE THE NUMBERS, IN PAIRS, that are at the END of the stem. so you can only circle the numbers that are at the end, the ones that dont branch off into further numbers. ok? in this way, we find that we have four pairs of 2's. and we have one 2 thats all by itself :( ok... interesting... so four pairs of 2's, lets find [tex]2^{4}[/tex] (the exponent will be how many pairs you found). but we have one 2 thats all alone so lets put it in the radical... and the 16 we found as a result of
but DONT FORGET THE x's in this equation! [tex]x^{3}[/tex] to be exact. we can actually put one x outside the radical since [tex]x^{2}[/tex] under a radical just solves as x. the square root of [tex]x^{2}[/tex] is just x, so x is outside of the radical.
but remember that we were given x^{3} to start off with! so we are gonna have one x all by his or her lonesome.
our answer will then be.... [tex]16x\sqrt{2x}[/tex]
put the rest of your questions in their own posts on brainly because the other ones are too much work for just one question
