Given the data in the question;
Mass of the sky diver; [tex]m = 95kg[/tex]Since the skydiver is falling towards earth
Acceleration due to gravity; [tex]g = 9.8m/s^2[/tex]
1). What force does the effect of air resistance exert on the skydiver
Its is mentioned that the skydiver falling at a constant speed.
Without acceleration, the resultant force on the skydiver will be zero.
Hence, the force of air resistance on the skydiver will be his or her weight.
We know that, weight of an object is mass multiply be the force of gravity.
[tex]W = m \ * g[/tex]
So, Force of air resistance [tex]=W = m \ * g[/tex]
We substitute in our values
Force of air resistance [tex]=W =95kg \ * 9.8m/s^2[/tex]
Force of air resistance [tex]= 931kg.m/s^2[/tex]
Force of air resistance [tex]= 931N[/tex]
Therefore, the force exerted on the skydiver by the effect of air resistance is 931 Newton.
2). What force does the parachute rope exert on the skydiver when he reaches this constant speed
Here also, the skydiver reaches a constant speed, resultant force of the skydiver will be zero.
Force or Tension on the rope will be;
[tex]T = m \ * \ g[/tex]
We substitute our values into the equation
[tex]T = 95kg \ *\ 9.8m/s^2[/tex]
[tex]T= 931kg.m/s^2[/tex]
[tex]T = 931N[/tex]
Therefore, the rope of the parachute exerts a 931 Newton of force on the skydiver as he reaches constant speed.
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