What is the approximate energy of a photon having a frequency of 4 x 10^14 Hz? (h = 6.6 x 10^-34 Js)


A.

6.1 x 10^47 J


B.

4.0 x 10^14 J


C.

2.6 x 10^-19 J


D.

1.7 x 10^-48 J

Respuesta :

Answer:

option c

Explanation:

E = hf

E= energy

h = Planck constant

f = frequency

E = 6.6 X 10^-34 X 4 X 10^14

E = 2.64 X 10^-19J