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545J of work is done on a gas and changes the volume by −2.50L. What is the external pressure? Assume that the external pressure is constant over the change in volume. Give the answer to three significant figures.

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The external pressure, assuming that the external pressure is constant over the change in volume is -218 Pa.

Given the following data:

  • Work done = 545 Joules
  • Change in volume = −2.50L.

To find the external pressure, assuming that the external pressure is constant over the change in volume:

Mathematically, the work done by a system is given by the formula:

[tex]Work = P \delta V[/tex]

Where:

  • P is the pressure.
  • V is the volume.

Substituting the given parameters into the formula, we have;

[tex]545 = P(-2.50)\\\\P = \frac{545}{-2.50}[/tex]

External pressure, P = -218 Pa.

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