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Determine the equation of a circle with center at (8, 10) and radius 6. O 1) (X + 8)2 + (y + 10)2 = 36 2) (x + 8)2 + (y - 10)2 = 36 O 3) (x - 3)2 + (y - 10)2 = 6 + O4) (x - 3)2 + (y - 10)2 = 36​

Respuesta :

theleangreenbean

Answer:

[tex](x-8)^2+(y-10)^2=36[/tex]

Step-by-step explanation:

Hi there!

Equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is the radius

Plug in the center (8,10) and the radius 6:

[tex](x-8)^2+(y-10)^2=6^2\\(x-8)^2+(y-10)^2=36[/tex]

I hope this helps!