Answer:
[tex]n^{8}[/tex]
Step-by-step explanation:
Given the Quotient Rule of Exponents: [tex]\frac{a^{m}}{a^{n}} = a^{(m-n)}[/tex], you must subtract the exponents of each exponential expression (in fractions) before applying the Product Rule of Exponents (I will explain in a while what it means).
First, subtract the exponents of the first fraction, [tex]\frac{n^{5}}{n^{3}} = n^{(5 - 3)} = n^{2}[/tex]
Next, subtract the exponents of the second fraction: [tex]\frac{n^{9}}{n^{3}} = n^{(9 - 3)} = n^{6}[/tex]
At this point, we have the following exponential expressions: [tex]n^{2}[/tex] and [tex]n^{6}[/tex].
Since the required operation is multiplication, then you can apply the Product Rule of Exponents: [tex]a^{m} a^{n} = a^{(m+n)}[/tex]
[tex]n^{2}*n^{6} = n^{(2+6)} = n^{8}[/tex]
Therefore, the correct answer is [tex]n^{8}[/tex].
Please mark my answers as the Brainliest, if you find this helpful :)
