Answer:
[tex](2,1)[/tex]
Step-by-step explanation:
Let's first write down the first in traditional form:
[tex]\left \{3x-y=5} \atop {2x+y=5}} \right.[/tex]
At this point, let's choose the order we want to do it.
Eliminating x: Let's multiply the first by 2, the second by 3, and subtract one from the other. Rest is simple algebra
[tex]2I-3II: 6x-2y -6x-3y = 10-15\\-5y=-5 \rightarrow y=1[/tex]
Eliminating y: Let's simply add the two equations together. Rest is simple algebra
[tex]I+II:3x-y+2x+y = 10\\5x=10 \rightarrow x = 2[/tex]
