ayo help me please im dying of math
Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 3

Respuesta :

Step-by-step explanation:

relax ! don't panic. just breathe deeply and then focus again.

a geometric sequence means that every new term is created by multiplying the previous term by a constant factor.

this factor is given here as 3/2.

this is called common ratio, because of that building rule the ratio of 2 consecutive terms is

an/an-1 = factor = 3/2

the first term is 3.

so,

a1 = 3

a2 = a1×3/2 = 3×3/2 = 9/2

a3 = a2×3/2 = a1×3/2 × 3/2 = 3× 3/2 × 3/2 = 27/4

we see

an = an-1 × 3/2 = a1 × (3/2)^(n-1) = 3 × (3/2)^(n-1)

and therefore

a8 = 3 × (3/2)⁷ = 3× 2187/128 = 6561/128 = 51.2578125