The nth term of a sequence is 3n2 - n + 10 where n is a positive integer. Which term in the sequence is equal to 54?​

The nth term of a sequence is 3n2 n 10 where n is a positive integer Which term in the sequence is equal to 54 class=

Respuesta :

Answer:

4th term

Step-by-step explanation:

Equate the nth term formula to 54 and solve for n

3n² - n + 10 = 54 ( subtract 54 from both sides )

3n² - n - 44 = 0

Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term.

product = 3 × - 44 = - 132 and sum = - 1

The factors are - 12 and + 11

Use these factors to split the n- term

3n² - 12n + 11n - 44 = 0 ( factor the first/second and third/fourth terms )

3n(n - 4) + 11(n - 4) = 0 ← factor out (n - 4) from each term

(n - 4)(3n + 11) = 0

Equate each factor to zero and solve for n

n - 4 = 0 ⇒ n = 4

3n + 11 = 0 ⇒ 3n = - 11 ⇒ n = - [tex]\frac{11}{3}[/tex]

Since n > 0 then n = 4

3n^2 - n + 10 = 54
3n^2 - n - 44 = 0

Using factoring-

(3n + 11)(n - 4) = 0

n = -11/3 or 4

Since n is positive, it should be 4