PLEASE HELP!! The figure below shows a line graph and two shaded triangles that are similar:

A line is shown on a coordinate grid. The x axis values are from negative 10 to positive 10 in increments of 2 for each grid line. The y axis values are from negative 5 to positive 5 in increments of 1 for each grid line. The line passes through the ordered pairs negative 6, negative 3, and 0, 0, and 6, 3. A shaded right triangle is formed so that its hypotenuse is from ordered pair 0, 0 labeled O to 4, 2 labeled A, one leg is from 0, 0 to 4,0, and the second leg is from 4,0 to 4, 2. Another shaded right triangle is formed with the hypotenuse is from 4, 2 to 6, 3 labeled B, one leg is from 4, 2 to 6, 2, and the second leg is from 6, 2 to 6, 3.

Which statement about the slope of the line is true?

It is fraction 1 over 2 throughout the line.
It is 2 throughout the line.
The slope from point O to point A is fraction 1 over 2 times the slope of the line from point A to point B.
The slope from point O to point A is 2 times the slope of the line from point A to point B.

Respuesta :

The slope of the line of the graph is given by the ratio of the change in y-

coordinates to the change in the x-coordinates of the line.

The statement that is true about the slope of the line is; it is  [tex]\dfrac{1}{2}[/tex] throughout

the line.

Reasons:

The given parameter are;

The ordered pair through which the line passes = (-6, -3), and (0, 0) and (6, 3)

Points on the hypotenuse of the shaded right triangle = O(0, 0), and A(4, 2)

Points on the leg of the right triangle = (0, 0) to (4, 0)

Points on the second leg of the right triangle = (4, 0) to (4, 2)

Second right triangle;

Points on the hypotenuse = A(4, 2) to B(6, 3)

One leg of the right triangle extends from (4, 2) to (6, 2)

Second leg extends from  (6, 2) to (6, 3)

[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

[tex]\mathrm{Slope, \, of \ first \ triangle, \, m} =\dfrac{2-0}{4-0} = \dfrac{1}{2}[/tex]

[tex]x^{2} \mathrm{Slope, \, of \ second \ triangle, \, m} =\dfrac{3-2}{6-4} = \mathbf{\dfrac{1}{2}}[/tex]

Therefore;

The slope is [tex]\dfrac{1}{2}[/tex] throughout the line

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