3. A spring extends by 0.04 m when a force of 3N is applied.

a. Calculate the spring constant of the spring.


b. Calculate the extension of the spring when a force of 6N is applied, assuming the spring has not reached its elastic limit ​

Respuesta :

Hooke's law allows to find the results for the questions about the spring are:  

    a) The spring constant is: k = 75 N / m

    b) The elongation is: x = 0.08 m

Hooke's law states that the restoring force in a spring is proportional to the elongation of the spring from its equilibrium position.

             F = - k x

Where f is the force, k is the spring constant, and x is the displacement.

a) Indicate that the elongation is 0.04 m and the applied force is 3N.

           [tex]k = \frac{F}{x}[/tex]  

           k = [tex]\frac{3}{0.04}[/tex]  

           k = 75 N / m

b) They ask the extension of the spring when a force of 6 N is applied.

         [tex]x= \frac{F}{k}[/tex]  

          x = [tex]\frac{6}{75}[/tex]  

          x = 0.08 m

In conclusion using hooke's law we can find the results for the questions about the spring are:  

    a) The spring constant is: k = 75 N / m

    b) The elongation is: x = 0.08 m

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