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A quantity of electricity equal to 9.439 x 104 C passes through a galvanic cell that has an Ni(s) anode. Compute the maximum chemical amount, in moles, of Ni2 (aq) that can be released into solution.

Respuesta :

oladayoademosu

The maximum chemical amount in moles of Ni₂ (aq) that can be released into the solution is 0.978 mol.

Using Q = nF where Q = quantity of electricity = 9.439 × 10⁴ C = 94390, n = number of moles of NI₂ (aq) and F = Faraday's constant = 96485 C/mol

Making n subject of the formula, we have

n = Q/F

substituting the values of the variables into the equation, we have

n = Q/F

n = 94390 C/96485C/mol

n = 0.978 mol

So, the maximum chemical amount in moles of Ni₂ (aq) that can be released into the solution is 0.978 mol.

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