If the initial pressure of a gas in a container was 0.85 atm, what is the new pressure after the volume is reduced from 10 mL to 2 mL at constant temperature

Respuesta :

Taking into account the Boyle's Law, the new pressure is 4.25 atm.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls.

In this way pressure and volume are related, determining Boyle's law, one of the gas laws, which says:

"The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P×V = k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1×V1= P2×V2

In this case, you know:

  • P1= 0.85 atm
  • V1= 10 mL
  • P2=?
  • V2= 2 mL

Replacing in Boyle's Law:

0.85 atm× 10 mL= P2× 2 mL

Solving:

P2= (0.85 atm× 10 mL)÷ 2 mL

P2= 4.25 atm

In summary, the new pressure is 4.25 atm.

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