At where:
Q = amount of sensible heat (cal or J).
C = specific heat of the substance constituting the body (cal / g ° C or J / kg ° C).
M = body mass (g or kg).
Δθ = temperature variation (° C).
T = final temperature
To = Initial temperature
Data:
Q = 10 calories
M = 2 grams
C (ice)= 0.550 cal / g ° C
To = -30 ° C
T =?
Formula:
Q = m * c * Δθ
Resolution:
Substitute
Q = m * c * Δθ
10 = 2 * 0.550 * [T-To]
10 = 1.1 * [T-(-30)]
10 = 1.1 * [T+30]
10 = 1.1T + 33
-1.1T = 33 - 10
-1.1T = 23 .(-1)
1.1T = - 23
T = [tex] \frac{-23}{1.1} [/tex]
T ≈ - 20.90 ° C (the final temperature of the ice)
