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Is △DBE similar to △ABC? If so, which postulate or theorem proves these two triangles are similar?

​△DBE​ is similar to ​△ABC​ by the ​SAS Similarity Theorem​.

​△DBE​ is similar to ​△ABC​ by the ​SSA Similarity Theorem​.

​△DBE​ is similar to ​△ABC​ by the ​SSS Similarity Theorem​.

​△DBE​ is not similar to ​△ABC​.

Is DBE similar to ABC If so which postulate or theorem proves these two triangles are similarDBE is similar to ABC by the SAS Similarity TheoremDBE is similar t class=

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Medunno13

Answer: ​△DBE​ is similar to ​△ABC​ by the ​SAS Similarity Theorem​.

Step-by-step explanation:

[tex]\frac{AB}{BD}=\frac{22}{10}=\frac{11}{5}\\\\\frac{BC}{BE}=\frac{33}{15}=\frac{11}{5}[/tex]

Also, [tex]\angle B \cong \angle B[/tex] by the reflexive property, so the triangles are similar by SAS.

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