Respuesta :

Answer:

  • ∆E = 16 KJ

Explanation:

Given:

  • A gas absorbs 45 KJ of heat
  • Work done = 29 KJ

Calculation:

∆E = q + w

∆E = 45KJ + (-29KJ)

∆E = 45KJ - 29KJ

∆E = 16KJ