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fieryanswererft

Answer:

area of this circle: 490.6 inch²

Step-by-step explanation:

area of circle: π(radius)²

Here the diameter is given 25 inch, so the radius will be half: 25/2 → 12.5 in

using the formula:

3.14(12.5)²

490.625 inch²

490.6 inch²____rounded to nearest tenth.

WindyMint

Given:

[tex] \\ [/tex]

  • Diameter of circle = 25in.

[tex] \\ [/tex]

To find:

[tex] \\ [/tex]

  • Area of circle.

[tex] \\ [/tex]

Explanation:

[tex] \\ [/tex]

So as Diameter is given , let's covert it into radius.

We know:

[tex] \\ [/tex]

[tex] \bigstar \boxed{ \rm Diameter \: of \: circle \: = 2 \times radius}[/tex]

[tex] \\ \\ [/tex]

[tex] \hookrightarrow \sf Diameter \: of \: circle \: = 2 \times radius \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \hookrightarrow \sf 25 = 2 \times radius \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \hookrightarrow \sf radius \: = \dfrac{25}{2} [/tex]

[tex] \\ \\ [/tex]

[tex] \hookrightarrow \bf radius \: = 12.5 in.[/tex]

Now Let's find circumference of circle:

we know:-

[tex] \\ \\ [/tex]

[tex] \bigstar \boxed{ \rm Circumference \: of \: circle \: = \pi radius^2}[/tex]

[tex] \\ [/tex]

So:-

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf Circumference \: of \: circle \: = \pi radius^2\\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf Circumference \: of \: circle \: = 3.14\times (12.5)^2\\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf Circumference \: of \: circle \: = 3.14 \times 156.25\\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \bf Circumference \: of \: circle \: = 490.63\\[/tex]

[tex] \\ \\ [/tex]

[tex] \bf\dag \underline {\blue{\frak{ Circumference \: of \: circle \: = 490.63 in(approx)}}}[/tex]

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