Respuesta :
The slope is the rate of change of the y-value, which is the coefficient of
x when the coefficient of y is 1.
Response:
- m = 2
- m = [tex]-\frac{1}{4}[/tex]
- m = [tex]-\frac{1}{7}[/tex]
- m = [tex]\frac{1}{2}[/tex]
- m = -7
- m = 4
- m = -4, b = 6
- m = 0, b = [tex]-\frac{1}{4}[/tex]
- m = -4, b = -1
- m = 6, b = -4
- m = [tex]-\frac{1}{4}[/tex], b = 2
- m = [tex]\frac{1}{6}[/tex], b = [tex]\frac{5}{6}[/tex]
- m = 8, b = 50
- What the Pelican said was; PUT IT ON MY BILL
Which methods are used to find the slope and intercept of a line?
The slopes are;
1. The common difference between the y-values is constant, therefore,
the points are points on a straight line, which gives;
[tex]Slope, \ m = \dfrac{-8 - (-12)}{-8 - (-10)} = \dfrac{4}{2} = \underline{2}[/tex]
2. The slope of the line is found as follows;
[tex]Slope, \ m = \dfrac{1 - 2}{0 - (-4)} = \underline{-\dfrac{1}{4}}[/tex]
[tex]3. \hspace{0.15 cm} Slope, \ m = \dfrac{-8 - (-7)}{0 - (-7)} = \underline{-\dfrac{1}{7}}[/tex]
[tex]4. \hspace{0.15 cm} Slope, \ m = \dfrac{3 - 2}{0 - (-2)} = \underline{ \dfrac{1}{2}}[/tex]
[tex]5. \hspace{0.15 cm} Slope, \ m = \dfrac{-25 - (-11)}{4 - 2} = -\dfrac{14}{2} = \underline{-7}[/tex]
[tex]6. \hspace{0.15 cm} Slope, \ m = \dfrac{-14 - (-38)}{-5 - (-11)} = \dfrac{24}{6} = \underline{4}[/tex]
The value of the slope, m, and the y-intercept, b, are the coefficient of x and
the constant when the coefficient of y is 1.
Which gives;
7. The slope, m = -4, the y-intercept, b = 6
8. The slope, m = 0, the y-intercept, b = [tex]\underline{-\frac{1}{4}}[/tex]
9. The slope, m = -4, the y-intercept, b = -1
10. The slope, m = 6, the y-intercept b = -4
11. The slope, m = [tex]\underline{-\frac{1}{4}}[/tex], the y-intercept is b = 2
12. The slope, m = [tex]\underline{\frac{1}{6}}[/tex], the y-intercept b = [tex]\underline{\frac{5}{6}}[/tex]
13. The slope, m = 8, the y-intercept, b = 50
In the possible letter code from a similar question, we have;
[tex]\begin{array}{ccccccccccccccccc}7&2&12&&5&8&&1&9&&10&3&&13&4&11&6\\P&U&T&&I&T&&O&N&&M&Y&&B&I&L&L\end{array}\right][/tex]
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