3.4 Puzzle Time What Did The Pelican Say When It Finished Shopping? Write the letter of each answer in the box containing the exercise number. Answers Find the slope of the line that passes through the given points. 1. (-10, -12), (-8, -8), (-6. - 4), (-4, 0) 1. m = M. m = 6, 6 = -4 2. (-4, 2), (0, 1), (4,0), (8, -1) 3. (-7, -7), (0, -8), (7, -9), (14,-10) U. m3 4. (-2, 2), (0, 3), (2, 4), (4, 5) N. m = -4, b = -1 5. (2. -11), (4, -25), (6,-39), (8, -53) P. m = -4, b = 6 I m = -7 6. (-11, -38), (-5, -14), (1, 10), (7, 34) L. m = 16=2 Find the slope and the y-intercept of the graph of the linear equation. 7. y = - 4x + 6 . m = 2 L. m = 4 8. y = - T. m = 0,6 = A 9. 4r + y = -1 B. m = 8,5 = 50 10. y = 6.r - 4 Y m = - 11. -r - 4y + 8 = 0 = -1 T. ms, 12. 2.r - 12y + 10 = 0 13. The function C(x) = 8.0 + 50 represents the cost C (in dollars) of towing a vehicle, where x is the number of miles the vehicle is towed. Identify the slope and y-intercept 6 11 3 13 10 9 1 8 7 2. 12 5 Ideas Learning, LLC

Respuesta :

The slope is the rate of change of the y-value, which is the coefficient of

x when the coefficient of y is 1.

Response:

  1. m  = 2
  2. m = [tex]-\frac{1}{4}[/tex]
  3. m = [tex]-\frac{1}{7}[/tex]
  4. m = [tex]\frac{1}{2}[/tex]
  5. m = -7
  6. m = 4
  7. m = -4, b = 6
  8. m = 0, b = [tex]-\frac{1}{4}[/tex]
  9. m = -4, b = -1
  10. m = 6, b = -4
  11. m =  [tex]-\frac{1}{4}[/tex], b = 2
  12. m =  [tex]\frac{1}{6}[/tex], b =  [tex]\frac{5}{6}[/tex]
  13. m = 8, b = 50

  • What the Pelican said was; PUT IT ON MY BILL

Which methods are used to find the slope and intercept of a line?

The slopes are;

1. The common difference between the y-values is constant, therefore,

the points are points on a straight line, which gives;

[tex]Slope, \ m = \dfrac{-8 - (-12)}{-8 - (-10)} = \dfrac{4}{2} = \underline{2}[/tex]

2. The slope of the line is found as follows;

[tex]Slope, \ m = \dfrac{1 - 2}{0 - (-4)} = \underline{-\dfrac{1}{4}}[/tex]

[tex]3. \hspace{0.15 cm} Slope, \ m = \dfrac{-8 - (-7)}{0 - (-7)} = \underline{-\dfrac{1}{7}}[/tex]

[tex]4. \hspace{0.15 cm} Slope, \ m = \dfrac{3 - 2}{0 - (-2)} = \underline{ \dfrac{1}{2}}[/tex]

[tex]5. \hspace{0.15 cm} Slope, \ m = \dfrac{-25 - (-11)}{4 - 2} = -\dfrac{14}{2} = \underline{-7}[/tex]

[tex]6. \hspace{0.15 cm} Slope, \ m = \dfrac{-14 - (-38)}{-5 - (-11)} = \dfrac{24}{6} = \underline{4}[/tex]

The value of the slope, m, and the y-intercept, b, are the coefficient of x and

the constant when the coefficient of y is 1.

Which gives;

7. The slope, m = -4, the y-intercept, b = 6

8. The slope, m = 0, the y-intercept, b = [tex]\underline{-\frac{1}{4}}[/tex]

9. The slope, m = -4, the y-intercept, b = -1

10. The slope, m = 6, the y-intercept b = -4

11. The slope, m = [tex]\underline{-\frac{1}{4}}[/tex], the y-intercept is b = 2

12. The slope, m =  [tex]\underline{\frac{1}{6}}[/tex], the y-intercept b =  [tex]\underline{\frac{5}{6}}[/tex]

13.  The slope, m = 8, the y-intercept, b = 50

In the possible letter code from a similar question, we have;

[tex]\begin{array}{ccccccccccccccccc}7&2&12&&5&8&&1&9&&10&3&&13&4&11&6\\P&U&T&&I&T&&O&N&&M&Y&&B&I&L&L\end{array}\right][/tex]

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