What is the amount in grams of EDTA needed to make 329.5 mL of a 0.03 M EDTA solution. The molar mass of EDTA is 374 g/mol. (Only enter numeric value in the answer, do not include the unit)

Respuesta :

Taking into account the definition of molarity and molar mass, the amount of mass of EDTA needed to make 329.5 mL of a 0.03 M EDTA solution is 3.69699 grams.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units .

Definition of molar mass

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Mass of EDTA

In this case, you need to make 329.5 mL of a 0.03 M EDTA solution. Then, you know:

  • Molarity= 0.03 M
  • number of moles= ?
  • Volume= 329.5 mL= 0.3295 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

[tex]0.03 M=\frac{number of moles}{0.3295 L}[/tex]

Solving:

0.03 M× 0.3295 L= number of moles

number of moles= 0.009885 moles

Now, knowing that the molar mass of EDTA is 374[tex]\frac{grams}{mole}[/tex], the mass of EDTA needed is calculated by:

0.009885 moles×374[tex]\frac{grams}{mole}[/tex]= 3.69699 grams

Finally, the amount of mass of EDTA needed to make 329.5 mL of a 0.03 M EDTA solution is 3.69699 grams.

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