Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.
For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.
The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
In this problem:
The probability that at least 12 of them need correction for their eyesight is given by:
[tex]P(X \geq 12) = P(X = 12) + P(X = 13)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299[/tex]
[tex]P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334[/tex]
Then:
[tex]P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163[/tex]
The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.
More can be learned about the binomial distribution at https://brainly.com/question/24863377