Respuesta :

Answer:

56.1 ppm

Explanation:

Molar mass of KOH is 56.1g

Mass of 0.01 mole of KOH = 0.561g

Mass of water = 10kg = 10000g

Concentration of KOH in ppm = 0.561 / 10000 * 1000000

= 56.1 ppm

Moles of KOH=0.01mol

  • Mass of KOH=0.001(56.1)=0.561g

Concentration of KOH:-

[tex]\\ \rm\Rrightarrow 0.561/10=0.561nm[/tex]

[tex]\\ \rm\Rrightarrow 56.1ppm[/tex]