Respuesta :
The relative molar amounts of the given species are;
KnO₃ = 0 M
K⁺ = NO₃⁻ = 0.1 M.
H₃O⁺ = OH⁻ = 1 × 10⁻⁷ M
H₂O = 55.56 M
What is the Relative Molar Amount?
KnO₃ → K⁺ + NO₃⁻
In this dissociation, we see that 1 mole of KnO₃ produces 1 mol of K⁺ and 1 mol of NO₃⁻.
Thus, concentration of KnO₃ is 0 M while the concentration of K⁺ and NO₃⁻ are both 0.1 M.
Now, concentrations of H₃O⁺ and OH⁻ depends solely on the autoionization of water.
Thus, concentration of H₃O⁺ is equal to concentration of OH⁻ = 1 × 10⁻⁷ M. Finally, concentration of H₂O is calculated from it's (1 g/mL) and molar mass of H₂O is 18 g/mol. Thus, concentration = (1/18) * 1000= 55.56 M
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