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A supply capsule w/ crew approaches a spy satellite at a relative speed of 0.250 m/s so as to dock. The astronauts will then repair said spy satellite. The supply capsule has a mass of 4000 kg, and the spy satellite has a mass of 7500kg. a. Calculate the final velocity (after docking) by using the frame of reference in which the Spy satellite appears to be originally at rest. b. What is the loss of kinetic energy in this inelastic collision

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okpalawalter8

The final velocity and the loss of kinetic energy is mathematically given as

  • vf = 0.087 m/s
  • L-K.E= 81.5 J

What are the final velocity and the loss of kinetic energy?

Question Parameters:

Generally, the equation for the conservation of momentum   is mathematically given as

m1v1 = m2v2

(7500 + 4000) * vf = 4000 * 0.250

vf = 0.087 m/s

b)

Generally, the equation for the loss of kinetic energy  is mathematically given as

loss in kinetic energy = initial kinetic energy - final kinetic energy

Therefore

L-K.E= 0.50 * 4000 * 0.25^2 - 0.50 * (4000 + 7500) * 0.087^2

L-K.E= 81.5 J

In conclusion, the final velocity and the loss of kinetic energy

vf = 0.087 m/s

L-K.E= 81.5 J

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