From the calculations and results obtained, the pH of the solution is 12.85. This implies that the solution is basic or we can say it is alkaline.
pH is a scale that shows the acidity or alkalinity of a solution.
Number of moles of hydrogen cyanide = 0.410 M * 16.8 /1000 L = 0.0069 moles
Number of moles of NaOH = 0.408 M * 25.3/1000 L = 0.01 moles
Since the reaction is 1:1, hydrogen cyanide is the limiting reactant.
Number of moles of NaOH left over = 0.01 moles - 0.0069 moles
= 0.0031 moles
Total volume = 16.8 mL + 25.3 mL = 42.1 mL or 0.042 L
Molarity of left over hydroxide ions = 0.0031 moles /0.042 L
= 0.07 M
pOH = - log(0.07 M) = 1.15
pH = 14 - 1.15 = 12.85
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