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An apparatus for measuring thermal conductivity employs an electrical heater sandwiched between two identical samples of diameter 25 mm and length 60 mm, which are pressed between plates maintained at a uniform temperature To = 77°C by a circulating fluid. A conducting grease is placed between all the surfaces to ensure good thermal contact. Differential thermocouples are imbedded in the samples with a spacing of 15 mm. The lateral sides of the samples are insulated to ensure one-dimensional heat transfer through the samples.


Required:

a. What is the thermal conductivity of the stainless steel sample material?

b. What is the average temperature of the samples?

Respuesta :

onyebuchinnaji

The thermal conductivity of the stainless steel sample material is 30Q/ΔT.

Thermal conductivity

The thermal conductivity of the stainless steel sample material is calculated as follows;

[tex]k = \frac{Ql}{A\Delta T}[/tex]

where;

Q is quantity of heat transferred

  • l is the length of heat flow = 15 mm = 0.015 m
  • A is the area
  • ΔT is change in temperature

Area = πd²/4

Area = π(25 x 10⁻³)²/4

Area = 0.0005 m³

[tex]k = \frac{Q \times 0.015}{0.0005 \times \Delta T} \\\\k = 30\frac{Q}{\Delta T}[/tex]

Thus, the thermal conductivity of the stainless steel sample material is 30Q/ΔT.

More information is needed on the heat supplied to the samples and the final temperature.

Learn more about thermal conductivity here: https://brainly.com/question/11213835

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