contestada

Determine and state an equation of the line perpendicular to the lines 5x-4y=10 and passing through the point (5,12). in point-slope form.

Please help I will mark branilest!!! and give 100 points

Respuesta :

CalculationStation
Perpendicular lines have slopes that are negative reciprocals of one another.

slope intercept form (y = mx + b) of the first equation will help us find the slope of the first line: where m = slope

5x-4y=10
-4y=-5x + 10
y=-5/-4 x + 10/-4
y=5/4 x -2.5

if the slope of this line is 5/4 then the slope of the perpendicular line is -4/5.

Therefore with the given information we can state the equation of the second line in point slope form (y-y,) = m(x-x,)

the coordinates of (5,12) can are substituted for x, and y,

so the answer is

(y-12) = -4/5(x-5)

I hope this helped and is BRAINLIEST!

Good luck with your studies!

akposevictor

The equation of the line in point-slope form is: y - 12 = -4/5(x - 5).

What is the Equation of a Line in Point-slope Form?

It is given as, y - b = m(x - a), where (a, b) is a point on the line and m is the slope of the line.

Rewrite 5x-4y=10 in slope-intercept form:

-4y= - 5x + 10

y= -5x/-4 + (10/-4)

y = 5/4x - 5/2

The slope is 5/4

The line that is perpendicular to 5x-4y=10 will have a slope which is the negative reciprocal of 5/4, which is -4/5.

Substitute (5, 12) and -4/5 into y - b = m(x - a):

y - 12 = -4/5(x - 5) [point-slope form]

Learn more about point-slope form on:

https://brainly.com/question/24907633

#SPJ6

Otras preguntas