Respuesta :

Ankit

Answer:

[tex]\longmapsto \sf \: \: - 14x \cdot\sqrt{14x}[/tex]

Step-by-step explanation:

[tex] \sf \: if \: x > 0 [/tex]

[tex] \sf 6x \sqrt{14x} - 5 \sqrt{56 {x}^{3} } [/tex]

[tex] \sf Let's \: solve \: for \sqrt{56 {x}^{3} } \: first, \\\longmapsto \sf \sqrt{56 {x}^{3} } = \sqrt{14 \times 4 {x}^{2} \times x } \\ \sf \longmapsto \sqrt{56 {x}^{3} } = 4x \sqrt{14x} [/tex]

Substituting above value in given equation,

[tex]\longmapsto \sf 6x \sqrt{14x} - 5 \sqrt{56 {x}^{3} } \\ \longmapsto\sf 6x \sqrt{14x} - 5 \times 4x \sqrt{14x} \\ \longmapsto \sf \: 6x \sqrt{14x} - 20x \sqrt{14x} \\\longmapsto \sf \: \sqrt{14x}(6x - 20x) \\ \longmapsto \sf \: \: - 14x \cdot\sqrt{14x}[/tex]

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