Respuesta :

Answer:

arc UH = 67°

Step-by-step explanation:

the measure of a chord- chord angle is half the sum of the measures of the arcs intercepted by the angle and its vertical angle , then

[tex]\frac{1}{2}[/tex] ( BE + UH ) = ∠ BKE , that is

[tex]\frac{1}{2}[/tex] (119 + UH ) = 93° ( multiply both sides by 2 to clear the fraction )

119° + UH = 186° ( subtract 119° from both sides )

UH = 67°

devishri1977

Answer:

Step-by-step explanation:

∠HKU = ∠BKE   {Vertically opposite angles}

∠HKU = 93°

Angles fromed by insecting chords equals half the sum of intercepting arcs.

      [tex]\sf \angle HKU =\dfrac{1}{2}(arc \ HU + arc \ BE) \\\\ 93^ \circ = \dfrac{1}{2}(arc \ HU + 119)[/tex]

   93 *2 = arc HU + 119

   186    = arc HU + 119

186 - 119 = arc HU

arc HU = 67°

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