y = 2
To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.
[tex]\implies \text{Slope} = \dfrac{\text{Rise}}{\text{Run}} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
[tex]\implies \text{Slope} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
Substitute the coordinates of the given points:
[tex]\implies \text{Slope} = \dfrac{2 - 2}{-3 - 10 }[/tex]
Simplify the equation to determine the slope:
[tex]\implies \text{Slope} = \dfrac{0}{-3 - 10 }[/tex]
∴ 0 divided by ANY number is ALWAYS 0.
[tex]\implies \text{Slope} =0[/tex]
Point slope form formula: y - y₁ = m(x - x₁)
Substitute the values in the point slope form:
[tex]\implies \text{Equation of line:} \ y - y_{1} = m(x - x_{1} )[/tex]
[tex]\implies \text{Equation of line:} \ y - 2 = 0(x - 10)[/tex]
Simplify the equation to determine the equation of the line:
∴ Any number multiplied by 0 is 0.
[tex]\implies \text{Equation of line:} \ y - 2 = 0[/tex]
[tex]\implies \text{Equation of line:} \ y = 0 + 2[/tex]
[tex]\implies \text{Equation of line:} \ y = 2[/tex]
Thus, the equation of the line is y = 2.