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Which are solutions of x2 5x = 2? check all that apply. startfraction 5 over 2 endfraction startfraction startroot 33 endroot over 4 endfraction startfraction 5 over 2 endfraction startfraction startroot 33 endroot over 2 endfraction startfraction 5 over 2 endfraction minus startfraction startroot 33 endroot over 2 endfraction startfraction negative 5 over 2 endfraction minus startfraction startroot 33 endroot over 2 endfraction startfraction negative 5 over 2 endfraction startfraction startroot 33 endroot over 2 endfraction

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niejaharris664

Answer:

x = -5/2  + root(33)/2   or   x = -5/2 - root(33)/2

Step-by-step explanation:

ok so your computer is

saying:

x^2  + 5x = 2

and takes the 5 divides it by 2  and squares the result

x^2  + 5x  +  25/4    =   2 + 25 /4   but then   replaces a trinomial with a binomial

(x + 5/2)^2  =  2 + 25/4 =  33/4

solving

x = -5/2  + root(33/4)   or   x = -5/2 - root(33/4)

or

x = -5/2  + root(33)/2   or   x = -5/2 - root(33)/2

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