First rewrite the equation in slope intercept form
slope intercept form: y = mx + b [ where m is slope and b is y-intercept ]
[tex]\rightarrow \sf 8y = -2x+32[/tex]
[tex]\rightarrow \sf y =\dfrac{ -2x+32}{ 8}[/tex]
[tex]\rightarrow \sf y =\dfrac{ -2x}{ 8} + \dfrac{32}{8}[/tex]
[tex]\rightarrow \sf y =\dfrac{ -1}{ 4}x + 4[/tex]
comparing with y = mx + b
- slope: -1/4 and y-intercept: 4
x-intercept: ( then y will be 0 )
[tex]\hookrightarrow \sf -2x + 32 = 0[/tex]
[tex]\hookrightarrow \sf -2x = -32[/tex]
[tex]\hookrightarrow \sf x = 16[/tex]
In order to graph the line
- plot x = 16 on the x-axis coordinate: (16, 0)
- plot y = 4 on the y-axis coordinate: (0, 4)
- Then using a scale/ruler draw a straight line through this points.
Graph:
