Answer:
x ≤ 40
Step-by-step explanation:
Given:
[tex]\displaystyle \large{\dfrac{x}{-8} \geq -5}[/tex]
Multiply both sides by -8 to get clear out the denominator:
[tex]\displaystyle \large{\dfrac{x}{-8}\cdot (-8) \geq -5\cdot (-8)}\\\displaystyle \large{x\geq 40}[/tex]
Because the LHS (Left-Handed Side) expression is in negative, make sure not to forget to swap the sign from ≥ to ≤
Hence, the solution is x ≤ 40
