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Suppose you have drawn two cards: 10 of clubs and 4 of hearts. You now draw a third card from the remaining 50. What is the probability that the sum of all three cards is strictly larger than 21

Respuesta :

facundo3141592

The probability that the sum is strictly larger than 21 is P = 0.46

How to find the probability?

We already have a 10 and a 4, so: 10 + 4 = 14

To sum more than 21, we need to draw at least an 8.

On the deck there are:

  • 6 cards equal or larger than 8 of diamonds.
  • 6 cards equal or larger than 8 of clubs.
  • 6 cards equal or larger than 8 of spades
  • 5 cards equal or larger than 8 of hearts (because we already drew the 10).

So, 23 out of 50 cards meet our requirements. So the probability will be:

P = 23/50 = 0.46

If you want to learn more about probability, you can read:

https://brainly.com/question/251701

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