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Two similar waves are traveling through the same medium. Wave A has a frequency that is 3 times that of wave B.

How do their wavelengths compare?



λA=λBlambda sub cap A is equal to lambda sub cap b

λA=19λBlambda sub cap A is equal to 1 ninth lambda sub cap b

λA=3λBlambda sub cap A is equal to 3 lambda sub cap b

λA=13λB

Respuesta :

Relationship:-

[tex]\\ \sf\rightarrow \nu=\dfrac{v}{\lambda}[/tex]

  • nu is frequency
  • Lambda is wavelength

So

[tex]\\ \sf\rightarrow \nu\propto \dfrac{1}{\lambda}[/tex]

If frequency is 3 times more then wavelength is 3 times less

onyebuchinnaji

The wavelength of wave B will be greater than wavelength of wave A which has greater frequency.

What is wavelength?

The wavelength of a wave is the distance traveled by the wave.

The relationship between wavelength and frequency of a wave is given as;

v = fλ

λ = v/f

At a constant speed of sound, increase in frequency causes a decrease in the wavelength of a given wave.

Thus, the wavelength of wave B will be greater than wavelength of wave A which has greater frequency.

Learn more about wavelength here: https://brainly.com/question/10728818

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