11. Which of the following gives the correct relation between the acceleration due to gravity and period of a pendulum?
g = 2πLT2
g = 4π2LT2
g = 2πLT
g = 2π2LT

Please show all of your algebra.

Respuesta :

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

  • Derive g

[tex]\\ \rm\rightarrowtail T^2=4\pi^2\dfrac{l}{g}[/tex]

[tex]\\ \rm\rightarrowtail g=\dfrac{4\pi ^2\ell}{T^2}[/tex]

[tex]\\ \rm\rightarrowtail g=\left(\dfrac{2\pi\sqrt{l}}{T}\right)^2[/tex]