The expression x^2 + 6x + c is a quadratic expression, and the value of c that makes the trinomial a perfect square is 9
How to find the value of c that makes the trinomial a perfect square?
The expression is given as:
x^2 + 6x + c
Take the coefficient of 6
k = 6
Divide by 2
k/2 = 3
Take the square of both sides
(k/2)^2 = 9
The value of c is:
c = (k/2)^2 = 9
So, we have:
c = 9
Hence, the value of c that makes the trinomial a perfect square is 9
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