1. What is the magnitude and direction of RS with tail and head points R(4, -6) and S(-2, 1)?
a.9.2 units, 49.4° south of east
b.10.4 units, 40.6 ° south of east
c.9.2 units, 49.4 ° north of west
d. 10.4 units, 40.6 ° north of west

1 What is the magnitude and direction of RS with tail and head points R4 6 and S2 1 a92 units 494 south of east b104 units 406 south of east c92 units 494 north class=

Respuesta :

The magnitude and the direction of the vector formed by (4, 6) and (-2, 1) are [tex]\sqrt{85}[/tex] (approx. 9.2 units) and 49.4° north of west. (Correct choice: C)

How to find the magnitude and the direction of a vector

First, we need to determine the expression of [tex]\overrightarrow {RS}[/tex] by vector sum:

[tex]\overrightarrow{RS} = S(x,y) - R(x,y)[/tex]

[tex]\overrightarrow{RS} = (-2, 1) - (4, -6)[/tex]

[tex]\overrightarrow {RS} = (-6, 7)[/tex]

The magnitude and the direction of the vector are determined by Pythagorean theorem and inverse trigonometric functions, respectively:

Magnitude

[tex]\|\overrightarrow{RS}\| = \sqrt{(-6)^{2}+7^{2}}[/tex]

[tex]\|\overrightarrow{RS} \| = \sqrt{85}[/tex]

Direction

θ = tan⁻¹ (7/-6)

θ ≈ 130.601°

The magnitude and the direction of the vector formed by (4, 6) and (-2, 1) are [tex]\sqrt{85}[/tex] (approx. 9.2 units) and 49.4° north of west. (Correct choice: C) [tex]\blacksquare[/tex]

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