[tex]\rule{300}{1} \\ \diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]
What is the volume of a sphere with a diameter of 10m, rounded to the
nearest tenth of a cubic metre (m³)?
[tex]\diamond\large\textsf{\textbf{\underline{Answer and How to solve:-}}}[/tex]
[tex]\it{Volume\:of\:a\:sphere:-}[/tex]
[tex]\longmapsto\sf{V=\dfrac{4}{3} \pi r^3}[/tex]
[tex]\bold{\underline{Where:-}}[/tex]
Provided information:-
What we need in order to find the Volume:-
How to find the radius if we have the diameter?
- Since the radius is exactly one-half of the diameter, we divide the diameter by 2:-
[tex]\bold{r=d\div2}[/tex]
Replace d with 10:-
[tex]\bold{r=10\div2}[/tex]
Therefore, the radius of the sphere is
[tex]\bold{r=5}[/tex]
[tex]\rule{300}{1}[/tex]
✓ Now we have all the required information in order to find the volume of the sphere.
✳︎Substitute 5 in lieu of r:-
[tex]\bold{V=\dfrac{4}{3} \pi (5)^3}[/tex]
➪On simplification,
[tex]\bold{V=\dfrac{4}{2} \pi (125)}[/tex] ◈ Next, write the value of π (3.14…)
[tex]\bold{V=\dfrac{4}{3}\times3.14\times125}[/tex]
On further simplification,
[tex]\bold{V=\dfrac{4}{3} \times392.5}[/tex] Final Step:- Multiply the numbers.
[tex]\bold{V=523.3\:m^3}[/tex]
The answer has been rounded to the nearest tenth (one place after the decimal point)
Therefore, we conclude that the volume of the sphere is
[tex]\bold{V=523.3\:m^3}[/tex]
Good luck with your studies.
[tex]\rule{301}{1}[/tex]
