Respuesta :

Answer:

[tex]\frac{6}{k-6}[/tex]

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into [tex]\frac{(k+6)(k-6)}{(k-6)(k-10)}[/tex] ÷ [tex]\frac{(k-6)^2}{k(k-6)}[/tex] × [tex]\frac{6(k-10)}{k(k + 6)}[/tex]. We know that division is simply multiplication by the reciprocal, so that whole equation will turn into [tex]\frac{(k+6)(k-6)}{(k-6)(k-10)}[/tex] × [tex]\frac{k(k-6)}{(k-6)^2}[/tex] × [tex]\frac{6(k-10)}{k(k+6)}[/tex]. Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into [tex]\frac{6}{k-6}[/tex] which is our final answer, as it cannot be simplified further.

Hope this helped! :)

(K^2-36/k^2-16k+60)/(k^2-12k+36/k^2-6k)*(6k-60/k^2+6k)

=[(k^2-6^2)/(k-6)(k-10)]*[k(k-6)/(k-6)^2][6(k-10)/k(k+6)

=(k^2-6^2)(k/(k-6)^2)(6/k (k-6)
=6(k^2-6^2)/(k-6)^2(k+6)