Answer:
[tex]y=\frac{9\sqrt{2} }{2}[/tex] and x=9
Step-by-step explanation:
We can see that the triangle is a special triangle or isosceles triangle meaning that two angles/ two sides are the same.
[tex]y=\frac{9\sqrt{2} }{2}[/tex]
To solve for x use Pythagorean Theorem.
a^2 + b^2 = c^2.
[tex]\frac{9\sqrt{2} }{2} +\frac{9\sqrt{2} }{2}=x^2\\\\\frac{81}{2} +\frac{81}{2} =x^2\\\\\frac{162}{2} =x^2\\\\x=\sqrt{\frac{162}{2} } =\sqrt{81} =9\\\\x=9[/tex]
